What is the area of the walls of a house if it is 40' long, 20' wide, and 10' tall?

To determine the area of the walls of the house, we need to calculate the total surface area of the four walls. There are two pairs of opposing walls: the longer walls and the shorter walls.

The longer walls are each 40 feet long and 10 feet tall. Therefore, the area of one longer wall is calculated as follows:

Area of one longer wall = length × height = 40 ft × 10 ft = 400 ft².

Since there are two longer walls, the total area for these walls is:

Total area of longer walls = 2 × 400 ft² = 800 ft².

The shorter walls are each 20 feet long and also 10 feet tall. The area of one shorter wall is:

Area of one shorter wall = width × height = 20 ft × 10 ft = 200 ft².

Again, since there are two shorter walls, the total area for these walls is:

Total area of shorter walls = 2 × 200 ft² = 400 ft².

Adding the area of both pairs of walls together gives:

Total wall area = Total area of longer walls + Total area of shorter walls

Total wall area = 800 ft² + 400 ft² =